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1013442555107 is a prime number
BaseRepresentation
bin11101011111101011110…
…00100010110011100011
310120212212112221222102102
432233311320202303203
5113101012243230412
62053322531041015
7133135023404543
oct16576570426343
93525775858372
101013442555107
113608869a1574
121444b3a4016b
137474b25b668
143709d893323
151b5669858c2
hexebf5e22ce3

1013442555107 has 2 divisors, whose sum is σ = 1013442555108. Its totient is φ = 1013442555106.

The previous prime is 1013442555061. The next prime is 1013442555109. The reversal of 1013442555107 is 7015552443101.

It is a strong prime.

It is an emirp because it is prime and its reverse (7015552443101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1013442555107 is a prime.

Together with 1013442555109, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1013442555109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506721277553 + 506721277554.

It is an arithmetic number, because the mean of its divisors is an integer number (506721277554).

Almost surely, 21013442555107 is an apocalyptic number.

1013442555107 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013442555107 is an equidigital number, since it uses as much as digits as its factorization.

1013442555107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84000, while the sum is 38.

Adding to 1013442555107 its reverse (7015552443101), we get a palindrome (8028994998208).

The spelling of 1013442555107 in words is "one trillion, thirteen billion, four hundred forty-two million, five hundred fifty-five thousand, one hundred seven".