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10134433 is a prime number
BaseRepresentation
bin100110101010…
…001110100001
3201001212211101
4212222032201
510043300213
61001114401
7152066311
oct46521641
921055741
1010134433
1157a2171
123488a01
13213ab0a
1414bb441
15d52bdd
hex9aa3a1

10134433 has 2 divisors, whose sum is σ = 10134434. Its totient is φ = 10134432.

The previous prime is 10134419. The next prime is 10134437. The reversal of 10134433 is 33443101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8196769 + 1937664 = 2863^2 + 1392^2 .

It is an emirp because it is prime and its reverse (33443101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10134433 - 25 = 10134401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10134433.

It is not a weakly prime, because it can be changed into another prime (10134437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5067216 + 5067217.

It is an arithmetic number, because the mean of its divisors is an integer number (5067217).

Almost surely, 210134433 is an apocalyptic number.

It is an amenable number.

10134433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10134433 is an equidigital number, since it uses as much as digits as its factorization.

10134433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 10134433 is about 3183.4624232116. The cubic root of 10134433 is about 216.4045985951.

Adding to 10134433 its reverse (33443101), we get a palindrome (43577534).

The spelling of 10134433 in words is "ten million, one hundred thirty-four thousand, four hundred thirty-three".