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101344413253 = 195333916487
BaseRepresentation
bin101111001100010011…
…0010000011001000101
3100200120212101121112011
41132120212100121011
53130023132211003
6114320150254221
710215260204446
oct1363046203105
9320525347464
10101344413253
1139a86308736
1217784057371
1397311c7c45
144c958232cd
15298229e46d
hex1798990645

101344413253 has 4 divisors (see below), whose sum is σ = 106678329760. Its totient is φ = 96010496748.

The previous prime is 101344413239. The next prime is 101344413257. The reversal of 101344413253 is 352314443101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101344413253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101344413257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2666958225 + ... + 2666958262.

It is an arithmetic number, because the mean of its divisors is an integer number (26669582440).

Almost surely, 2101344413253 is an apocalyptic number.

It is an amenable number.

101344413253 is a deficient number, since it is larger than the sum of its proper divisors (5333916507).

101344413253 is an equidigital number, since it uses as much as digits as its factorization.

101344413253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5333916506.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 101344413253 its reverse (352314443101), we get a palindrome (453658856354).

The spelling of 101344413253 in words is "one hundred one billion, three hundred forty-four million, four hundred thirteen thousand, two hundred fifty-three".

Divisors: 1 19 5333916487 101344413253