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1013450335 = 5837613209
BaseRepresentation
bin111100011010000…
…000011001011111
32121121222121111121
4330122000121133
54033420402320
6244321431411
734054120462
oct7432003137
92547877447
101013450335
11480080267
1224349b567
13131c69371
149884d2d9
155de8b8aa
hex3c68065f

1013450335 has 16 divisors (see below), whose sum is σ = 1232794080. Its totient is φ = 799690240.

The previous prime is 1013450309. The next prime is 1013450351. The reversal of 1013450335 is 5330543101.

1013450335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 1013450335 - 25 = 1013450303 is a prime.

It is a super-2 number, since 2×10134503352 = 2054163163023224450, which contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 314211 + ... + 317419.

It is an arithmetic number, because the mean of its divisors is an integer number (77049630).

Almost surely, 21013450335 is an apocalyptic number.

1013450335 is a deficient number, since it is larger than the sum of its proper divisors (219343745).

1013450335 is an equidigital number, since it uses as much as digits as its factorization.

1013450335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4058.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 1013450335 is about 31834.7347248253. The cubic root of 1013450335 is about 1004.4634925922.

Adding to 1013450335 its reverse (5330543101), we get a palindrome (6343993436).

The spelling of 1013450335 in words is "one billion, thirteen million, four hundred fifty thousand, three hundred thirty-five".

Divisors: 1 5 83 415 761 3209 3805 16045 63163 266347 315815 1331735 2442049 12210245 202690067 1013450335