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10134917564437 is a prime number
BaseRepresentation
bin1001001101111011100000…
…1010010100100000010101
31022212212222211102122200101
42103132320022110200111
52312022302344030222
633315530012414101
72064136463620231
oct223367012244025
938785884378611
1010134917564437
113258215826096
12117826b477331
13586945a87aa3
1427076575b5c1
15128974877927
hex937b8294815

10134917564437 has 2 divisors, whose sum is σ = 10134917564438. Its totient is φ = 10134917564436.

The previous prime is 10134917564357. The next prime is 10134917564539. The reversal of 10134917564437 is 73446571943101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9912176986321 + 222740578116 = 3148361^2 + 471954^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10134917564437 is a prime.

It is a super-2 number, since 2×101349175644372 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10134917562437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5067458782218 + 5067458782219.

It is an arithmetic number, because the mean of its divisors is an integer number (5067458782219).

Almost surely, 210134917564437 is an apocalyptic number.

It is an amenable number.

10134917564437 is a deficient number, since it is larger than the sum of its proper divisors (1).

10134917564437 is an equidigital number, since it uses as much as digits as its factorization.

10134917564437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7620480, while the sum is 55.

The spelling of 10134917564437 in words is "ten trillion, one hundred thirty-four billion, nine hundred seventeen million, five hundred sixty-four thousand, four hundred thirty-seven".