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10135143553 is a prime number
BaseRepresentation
bin10010111000001101…
…00000010010000001
3222011100001122020011
421130012200102001
5131224044043203
64353411144521
7506105204323
oct113406402201
928140048204
1010135143553
11433102a3a7
121b6a2a5141
13c569b7182
146c20a1613
153e4ba576d
hex25c1a0481

10135143553 has 2 divisors, whose sum is σ = 10135143554. Its totient is φ = 10135143552.

The previous prime is 10135143541. The next prime is 10135143569. The reversal of 10135143553 is 35534153101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5937010704 + 4198132849 = 77052^2 + 64793^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10135143553 is a prime.

It is a super-2 number, since 2×101351435532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10135143853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5067571776 + 5067571777.

It is an arithmetic number, because the mean of its divisors is an integer number (5067571777).

Almost surely, 210135143553 is an apocalyptic number.

It is an amenable number.

10135143553 is a deficient number, since it is larger than the sum of its proper divisors (1).

10135143553 is an equidigital number, since it uses as much as digits as its factorization.

10135143553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 10135143553 its reverse (35534153101), we get a palindrome (45669296654).

The spelling of 10135143553 in words is "ten billion, one hundred thirty-five million, one hundred forty-three thousand, five hundred fifty-three".