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10135420117 is a prime number
BaseRepresentation
bin10010111000001111…
…00011110011010101
3222011100120200121021
421130013203303111
5131224131420432
64353421121141
7506110435534
oct113407436325
928140520537
1010135420117
1143311a9169
121b6a3b91b1
13c56a83014
146c213431b
153e4c0c697
hex25c1e3cd5

10135420117 has 2 divisors, whose sum is σ = 10135420118. Its totient is φ = 10135420116.

The previous prime is 10135420093. The next prime is 10135420121. The reversal of 10135420117 is 71102453101.

10135420117 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10098039121 + 37380996 = 100489^2 + 6114^2 .

It is an emirp because it is prime and its reverse (71102453101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10135420117 - 227 = 10001202389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10135420091 and 10135420100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10135423117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5067710058 + 5067710059.

It is an arithmetic number, because the mean of its divisors is an integer number (5067710059).

Almost surely, 210135420117 is an apocalyptic number.

It is an amenable number.

10135420117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10135420117 is an equidigital number, since it uses as much as digits as its factorization.

10135420117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 25.

Adding to 10135420117 its reverse (71102453101), we get a palindrome (81237873218).

The spelling of 10135420117 in words is "ten billion, one hundred thirty-five million, four hundred twenty thousand, one hundred seventeen".