10140131121 has 4 divisors (see below), whose sum is σ = 13520174832. Its totient is φ = 6760087412.

The previous prime is 10140131119. The next prime is 10140131123. The reversal of 10140131121 is 12113104101.

10140131121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (10140131119) and next prime (10140131123).

It is a cyclic number.

It is not a de Polignac number, because 10140131121 - 2¹ = 10140131119 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 10140131121.

It is not an unprimeable number, because it can be changed into a prime (10140131123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1690021851 + ... + 1690021856.

It is an arithmetic number, because the mean of its divisors is an integer number (3380043708).

Almost surely, 2^10140131121 is an apocalyptic number.

It is an amenable number.

10140131121 is a deficient number, since it is larger than the sum of its proper divisors (3380043711).

10140131121 is an equidigital number, since it uses as much as digits as its factorization.

10140131121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3380043710.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 10140131121 its reverse (12113104101), we get a palindrome (22253235222).

The spelling of 10140131121 in words is "ten billion, one hundred forty million, one hundred thirty-one thousand, one hundred twenty-one".