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10140341411 is a prime number
BaseRepresentation
bin10010111000110100…
…10101010010100011
3222011200211201100102
421130122111102203
5131231411411121
64354114413015
7506200323404
oct113432252243
928150751312
1010140341411
114333a5a652
121b6bb9116b
13c57ab7025
146c2a559ab
153e538090b
hex25c6954a3

10140341411 has 2 divisors, whose sum is σ = 10140341412. Its totient is φ = 10140341410.

The previous prime is 10140341377. The next prime is 10140341413. The reversal of 10140341411 is 11414304101.

10140341411 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10140341411 - 222 = 10136147107 is a prime.

Together with 10140341413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10140341413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5070170705 + 5070170706.

It is an arithmetic number, because the mean of its divisors is an integer number (5070170706).

Almost surely, 210140341411 is an apocalyptic number.

10140341411 is a deficient number, since it is larger than the sum of its proper divisors (1).

10140341411 is an equidigital number, since it uses as much as digits as its factorization.

10140341411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 10140341411 its reverse (11414304101), we get a palindrome (21554645512).

The spelling of 10140341411 in words is "ten billion, one hundred forty million, three hundred forty-one thousand, four hundred eleven".