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1014044551243 is a prime number
BaseRepresentation
bin11101100000110011100…
…00111110100001001011
310120221102111201112212121
432300121300332201023
5113103230401114433
62053502353552111
7133155653316403
oct16603160764113
93527374645777
101014044551243
11361065793139
12144641575637
1374815ba59a9
14371197d9803
151b59e749c2d
hexec19c3e84b

1014044551243 has 2 divisors, whose sum is σ = 1014044551244. Its totient is φ = 1014044551242.

The previous prime is 1014044551229. The next prime is 1014044551271. The reversal of 1014044551243 is 3421554404101.

It is a happy number.

1014044551243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1014044551243 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1014044551199 and 1014044551208.

It is not a weakly prime, because it can be changed into another prime (1014044551843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507022275621 + 507022275622.

It is an arithmetic number, because the mean of its divisors is an integer number (507022275622).

Almost surely, 21014044551243 is an apocalyptic number.

1014044551243 is a deficient number, since it is larger than the sum of its proper divisors (1).

1014044551243 is an equidigital number, since it uses as much as digits as its factorization.

1014044551243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38400, while the sum is 34.

Adding to 1014044551243 its reverse (3421554404101), we get a palindrome (4435598955344).

The spelling of 1014044551243 in words is "one trillion, fourteen billion, forty-four million, five hundred fifty-one thousand, two hundred forty-three".