10140603225133 has 4 divisors (see below), whose sum is σ = 10140675552540. Its totient is φ = 10140530897728.

The previous prime is 10140603225107. The next prime is 10140603225157. The reversal of 10140603225133 is 33152230604101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6282827994249 + 3857775230884 = 2506557^2 + 1964122^2 .

It is a cyclic number.

It is not a de Polignac number, because 10140603225133 - 2⁵ = 10140603225101 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10140603225095 and 10140603225104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10140603225733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35952988 + ... + 36233941.

It is an arithmetic number, because the mean of its divisors is an integer number (2535168888135).

Almost surely, 2^{10140603225133} is an apocalyptic number.

It is an amenable number.

10140603225133 is a deficient number, since it is larger than the sum of its proper divisors (72327407).

10140603225133 is an equidigital number, since it uses as much as digits as its factorization.

10140603225133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72327406.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 10140603225133 its reverse (33152230604101), we get a palindrome (43292833829234).

The spelling of 10140603225133 in words is "ten trillion, one hundred forty billion, six hundred three million, two hundred twenty-five thousand, one hundred thirty-three".