10141131421231 has 4 divisors (see below), whose sum is σ = 10490825608200. Its totient is φ = 9791437234264.

The previous prime is 10141131421219. The next prime is 10141131421271. The reversal of 10141131421231 is 13212413114101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10141131421231 - 2¹⁵ = 10141131388463 is a prime.

It is a super-3 number, since 3×10141131421231³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10141131421196 and 10141131421205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10141131421271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 174847093441 + ... + 174847093498.

It is an arithmetic number, because the mean of its divisors is an integer number (2622706402050).

Almost surely, 2^{10141131421231} is an apocalyptic number.

10141131421231 is a deficient number, since it is larger than the sum of its proper divisors (349694186969).

10141131421231 is an equidigital number, since it uses as much as digits as its factorization.

10141131421231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 349694186968.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 10141131421231 its reverse (13212413114101), we get a palindrome (23353544535332).

The spelling of 10141131421231 in words is "ten trillion, one hundred forty-one billion, one hundred thirty-one million, four hundred twenty-one thousand, two hundred thirty-one".