Base | Representation |
---|---|
bin | 10010111000111011… |
… | …00111011001011011 |
3 | 222011202110102212111 |
4 | 21130131213121123 |
5 | 131232121431021 |
6 | 4354145053151 |
7 | 506210536423 |
oct | 113435473133 |
9 | 28152412774 |
10 | 10141202011 |
11 | 4334498196 |
12 | 1b703271b7 |
13 | c58028965 |
14 | 6c2bdb483 |
15 | 3e54a08e1 |
hex | 25c76765b |
10141202011 has 2 divisors, whose sum is σ = 10141202012. Its totient is φ = 10141202010.
The previous prime is 10141202003. The next prime is 10141202039. The reversal of 10141202011 is 11020214101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10141202011 - 23 = 10141202003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10141201982 and 10141202000.
It is not a weakly prime, because it can be changed into another prime (10141202311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5070601005 + 5070601006.
It is an arithmetic number, because the mean of its divisors is an integer number (5070601006).
Almost surely, 210141202011 is an apocalyptic number.
10141202011 is a deficient number, since it is larger than the sum of its proper divisors (1).
10141202011 is an equidigital number, since it uses as much as digits as its factorization.
10141202011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 10141202011 its reverse (11020214101), we get a palindrome (21161416112).
The spelling of 10141202011 in words is "ten billion, one hundred forty-one million, two hundred two thousand, eleven".
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