Base | Representation |
---|---|
bin | 11101100000111100101… |
… | …01000100101010000001 |
3 | 10120221121211210202210121 |
4 | 32300132111010222001 |
5 | 113103410001404213 |
6 | 2053514131100241 |
7 | 133160603212126 |
oct | 16603625045201 |
9 | 3527554722717 |
10 | 1014121122433 |
11 | 3610a4a32211 |
12 | 144663141681 |
13 | 74828a054a3 |
14 | 37125a4c74d |
15 | 1b5a632288d |
hex | ec1e544a81 |
1014121122433 has 12 divisors (see below), whose sum is σ = 1050767710720. Its totient is φ = 978712294896.
The previous prime is 1014121122431. The next prime is 1014121122451. The reversal of 1014121122433 is 3342211214101.
It is not a de Polignac number, because 1014121122433 - 21 = 1014121122431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1014121122398 and 1014121122407.
It is not an unprimeable number, because it can be changed into a prime (1014121122431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1613716 + ... + 2152282.
Almost surely, 21014121122433 is an apocalyptic number.
It is an amenable number.
1014121122433 is a deficient number, since it is larger than the sum of its proper divisors (36646588287).
1014121122433 is an equidigital number, since it uses as much as digits as its factorization.
1014121122433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 540864 (or 540835 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1014121122433 its reverse (3342211214101), we get a palindrome (4356332336534).
The spelling of 1014121122433 in words is "one trillion, fourteen billion, one hundred twenty-one million, one hundred twenty-two thousand, four hundred thirty-three".
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