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1014121122433 = 2922239538567
BaseRepresentation
bin11101100000111100101…
…01000100101010000001
310120221121211210202210121
432300132111010222001
5113103410001404213
62053514131100241
7133160603212126
oct16603625045201
93527554722717
101014121122433
113610a4a32211
12144663141681
1374828a054a3
1437125a4c74d
151b5a632288d
hexec1e544a81

1014121122433 has 12 divisors (see below), whose sum is σ = 1050767710720. Its totient is φ = 978712294896.

The previous prime is 1014121122431. The next prime is 1014121122451. The reversal of 1014121122433 is 3342211214101.

It is not a de Polignac number, because 1014121122433 - 21 = 1014121122431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1014121122398 and 1014121122407.

It is not an unprimeable number, because it can be changed into a prime (1014121122431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1613716 + ... + 2152282.

Almost surely, 21014121122433 is an apocalyptic number.

It is an amenable number.

1014121122433 is a deficient number, since it is larger than the sum of its proper divisors (36646588287).

1014121122433 is an equidigital number, since it uses as much as digits as its factorization.

1014121122433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 540864 (or 540835 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1014121122433 its reverse (3342211214101), we get a palindrome (4356332336534).

The spelling of 1014121122433 in words is "one trillion, fourteen billion, one hundred twenty-one million, one hundred twenty-two thousand, four hundred thirty-three".

Divisors: 1 29 841 2239 64931 538567 1882999 15618443 452934847 1205851513 34969693877 1014121122433