101417714131 has 2 divisors, whose sum is σ = 101417714132. Its totient is φ = 101417714130.

The previous prime is 101417714119. The next prime is 101417714143. The reversal of 101417714131 is 131417714101.

It is a balanced prime because it is at equal distance from previous prime (101417714119) and next prime (101417714143).

It is a cyclic number.

It is not a de Polignac number, because 101417714131 - 2¹¹ = 101417712083 is a prime.

It is a super-2 number, since 2×101417714131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101417714093 and 101417714102.

It is not a weakly prime, because it can be changed into another prime (101417714191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50708857065 + 50708857066.

It is an arithmetic number, because the mean of its divisors is an integer number (50708857066).

Almost surely, 2^101417714131 is an apocalyptic number.

101417714131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101417714131 is an equidigital number, since it uses as much as digits as its factorization.

101417714131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2352, while the sum is 31.

The spelling of 101417714131 in words is "one hundred one billion, four hundred seventeen million, seven hundred fourteen thousand, one hundred thirty-one".