10142113433141 has 4 divisors (see below), whose sum is σ = 10164701659500. Its totient is φ = 10119525206784.

The previous prime is 10142113433077. The next prime is 10142113433147. The reversal of 10142113433141 is 14133431124101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2678950562500 + 7463162870641 = 1636750^2 + 2731879^2 .

It is a cyclic number.

It is not a de Polignac number, because 10142113433141 - 2⁶ = 10142113433077 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10142113433147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11294112506 + ... + 11294113403.

It is an arithmetic number, because the mean of its divisors is an integer number (2541175414875).

Almost surely, 2^{10142113433141} is an apocalyptic number.

It is an amenable number.

10142113433141 is a deficient number, since it is larger than the sum of its proper divisors (22588226359).

10142113433141 is an equidigital number, since it uses as much as digits as its factorization.

10142113433141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22588226358.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 10142113433141 its reverse (14133431124101), we get a palindrome (24275544557242).

The spelling of 10142113433141 in words is "ten trillion, one hundred forty-two billion, one hundred thirteen million, four hundred thirty-three thousand, one hundred forty-one".