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10143301307 = 67371505611
BaseRepresentation
bin10010111001001011…
…00111111010111011
3222011220102002120012
421130211213322323
5131233141120212
64354302052135
7506234432006
oct113445477273
928156362505
1010143301307
1143356a1447
121b70b7a04b
13c585b2349
146c31c653d
153e5767922
hex25c967ebb

10143301307 has 4 divisors (see below), whose sum is σ = 10144813656. Its totient is φ = 10141788960.

The previous prime is 10143301291. The next prime is 10143301361. The reversal of 10143301307 is 70310334101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10143301307 - 24 = 10143301291 is a prime.

It is a super-3 number, since 3×101433013073 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10143301367) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 746069 + ... + 759542.

It is an arithmetic number, because the mean of its divisors is an integer number (2536203414).

Almost surely, 210143301307 is an apocalyptic number.

10143301307 is a deficient number, since it is larger than the sum of its proper divisors (1512349).

10143301307 is an equidigital number, since it uses as much as digits as its factorization.

10143301307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1512348.

The product of its (nonzero) digits is 756, while the sum is 23.

Adding to 10143301307 its reverse (70310334101), we get a palindrome (80453635408).

The spelling of 10143301307 in words is "ten billion, one hundred forty-three million, three hundred one thousand, three hundred seven".

Divisors: 1 6737 1505611 10143301307