1014330525281 has 2 divisors, whose sum is σ = 1014330525282. Its totient is φ = 1014330525280.

The previous prime is 1014330525199. The next prime is 1014330525283. The reversal of 1014330525281 is 1825250334101.

1014330525281 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 849162250000 + 165168275281 = 921500^2 + 406409^2 .

It is a cyclic number.

It is not a de Polignac number, because 1014330525281 - 2¹⁰ = 1014330524257 is a prime.

It is a super-2 number, since 2×1014330525281² (a number of 25 digits) contains 22 as substring.

Together with 1014330525283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1014330525283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507165262640 + 507165262641.

It is an arithmetic number, because the mean of its divisors is an integer number (507165262641).

Almost surely, 2^{1014330525281} is an apocalyptic number.

It is an amenable number.

1014330525281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1014330525281 is an equidigital number, since it uses as much as digits as its factorization.

1014330525281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 35.

Adding to 1014330525281 its reverse (1825250334101), we get a palindrome (2839580859382).

The spelling of 1014330525281 in words is "one trillion, fourteen billion, three hundred thirty million, five hundred twenty-five thousand, two hundred eighty-one".