101433113 has 2 divisors, whose sum is σ = 101433114. Its totient is φ = 101433112.

The previous prime is 101433089. The next prime is 101433119. The reversal of 101433113 is 311334101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69022864 + 32410249 = 8308^2 + 5693^2 .

It is a cyclic number.

It is not a de Polignac number, because 101433113 - 2¹² = 101429017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101433091 and 101433100.

It is not a weakly prime, because it can be changed into another prime (101433119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50716556 + 50716557.

It is an arithmetic number, because the mean of its divisors is an integer number (50716557).

Almost surely, 2^101433113 is an apocalyptic number.

It is an amenable number.

101433113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101433113 is an equidigital number, since it uses as much as digits as its factorization.

101433113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 101433113 is about 10071.4007466688. The cubic root of 101433113 is about 466.3656818233.

Adding to 101433113 its reverse (311334101), we get a palindrome (412767214).

The spelling of 101433113 in words is "one hundred one million, four hundred thirty-three thousand, one hundred thirteen".