10143313002 has 24 divisors (see below), whose sum is σ = 21980592036. Its totient is φ = 3380579136.

The previous prime is 10143312983. The next prime is 10143313003. The reversal of 10143313002 is 20031334101.

10143313002 is a `hidden beast` number, since 101 + 433 + 130 + 0 + 2 = 666.

10143313002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 9996200361 + 147112641 = 99981^2 + 12129^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (10143313003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 85678 + ... + 166214.

Almost surely, 2^10143313002 is an apocalyptic number.

10143313002 is an abundant number, since it is smaller than the sum of its proper divisors (11837279034).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10143313002 is a wasteful number, since it uses less digits than its factorization.

10143313002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87542 (or 87539 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 10143313002 its reverse (20031334101), we get a palindrome (30174647103).

The spelling of 10143313002 in words is "ten billion, one hundred forty-three million, three hundred thirteen thousand, two".