Base | Representation |
---|---|
bin | 10010111001001011… |
… | …01111001110000111 |
3 | 222011220110121120121 |
4 | 21130211233032013 |
5 | 131233143044312 |
6 | 4354302442411 |
7 | 506234615122 |
oct | 113445571607 |
9 | 28156417517 |
10 | 10143331207 |
11 | 4335711959 |
12 | 1b70b93407 |
13 | c585c2b39 |
14 | 6c31d33b9 |
15 | 3e5771707 |
hex | 25c96f387 |
10143331207 has 2 divisors, whose sum is σ = 10143331208. Its totient is φ = 10143331206.
The previous prime is 10143331193. The next prime is 10143331283. The reversal of 10143331207 is 70213334101.
It is a weak prime.
It is an emirp because it is prime and its reverse (70213334101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10143331207 - 223 = 10134942599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10143331307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071665603 + 5071665604.
It is an arithmetic number, because the mean of its divisors is an integer number (5071665604).
Almost surely, 210143331207 is an apocalyptic number.
10143331207 is a deficient number, since it is larger than the sum of its proper divisors (1).
10143331207 is an equidigital number, since it uses as much as digits as its factorization.
10143331207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 10143331207 its reverse (70213334101), we get a palindrome (80356665308).
The spelling of 10143331207 in words is "ten billion, one hundred forty-three million, three hundred thirty-one thousand, two hundred seven".
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