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10143331207 is a prime number
BaseRepresentation
bin10010111001001011…
…01111001110000111
3222011220110121120121
421130211233032013
5131233143044312
64354302442411
7506234615122
oct113445571607
928156417517
1010143331207
114335711959
121b70b93407
13c585c2b39
146c31d33b9
153e5771707
hex25c96f387

10143331207 has 2 divisors, whose sum is σ = 10143331208. Its totient is φ = 10143331206.

The previous prime is 10143331193. The next prime is 10143331283. The reversal of 10143331207 is 70213334101.

It is a weak prime.

It is an emirp because it is prime and its reverse (70213334101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10143331207 - 223 = 10134942599 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10143331307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071665603 + 5071665604.

It is an arithmetic number, because the mean of its divisors is an integer number (5071665604).

Almost surely, 210143331207 is an apocalyptic number.

10143331207 is a deficient number, since it is larger than the sum of its proper divisors (1).

10143331207 is an equidigital number, since it uses as much as digits as its factorization.

10143331207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 10143331207 its reverse (70213334101), we get a palindrome (80356665308).

The spelling of 10143331207 in words is "ten billion, one hundred forty-three million, three hundred thirty-one thousand, two hundred seven".