10143344041 has 4 divisors (see below), whose sum is σ = 10169828352. Its totient is φ = 10116859732.

The previous prime is 10143343937. The next prime is 10143344051. The reversal of 10143344041 is 14044334101.

10143344041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10143344041 - 2¹¹ = 10143341993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10143343997 and 10143344015.

It is not an unprimeable number, because it can be changed into a prime (10143344051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13241581 + ... + 13242346.

It is an arithmetic number, because the mean of its divisors is an integer number (2542457088).

Almost surely, 2^10143344041 is an apocalyptic number.

It is an amenable number.

10143344041 is a deficient number, since it is larger than the sum of its proper divisors (26484311).

10143344041 is an equidigital number, since it uses as much as digits as its factorization.

10143344041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26484310.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 10143344041 its reverse (14044334101), we get a palindrome (24187678142).

The spelling of 10143344041 in words is "ten billion, one hundred forty-three million, three hundred forty-four thousand, forty-one".