Base | Representation |
---|---|
bin | 10010111001001111… |
… | …01011000011101111 |
3 | 222011221102101101021 |
4 | 21130213223003233 |
5 | 131233310312242 |
6 | 4354321355011 |
7 | 506242130011 |
oct | 113447530357 |
9 | 28157371337 |
10 | 10143838447 |
11 | 4335a28a66 |
12 | 1b71198a67 |
13 | c5873c992 |
14 | 6c32c61b1 |
15 | 3e5821b67 |
hex | 25c9eb0ef |
10143838447 has 4 divisors (see below), whose sum is σ = 10144922560. Its totient is φ = 10142754336.
The previous prime is 10143838429. The next prime is 10143838469. The reversal of 10143838447 is 74483834101.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74483834101 = 95087 ⋅783323.
It is a cyclic number.
It is not a de Polignac number, because 10143838447 - 27 = 10143838319 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10143838547) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 527898 + ... + 546775.
It is an arithmetic number, because the mean of its divisors is an integer number (2536230640).
Almost surely, 210143838447 is an apocalyptic number.
10143838447 is a deficient number, since it is larger than the sum of its proper divisors (1084113).
10143838447 is an equidigital number, since it uses as much as digits as its factorization.
10143838447 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1084112.
The product of its (nonzero) digits is 258048, while the sum is 43.
The spelling of 10143838447 in words is "ten billion, one hundred forty-three million, eight hundred thirty-eight thousand, four hundred forty-seven".
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