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101441003561 is a prime number
BaseRepresentation
bin101111001111001011…
…0101110000000101001
3100200211121010220111222
41132132112232000221
53130222344103221
6114333520431425
710220542206032
oct1363626560051
9320747126458
10101441003561
113a025890437
12177b0478575
139748216781
144ca45a7a89
15298a9cd9ab
hex179e5ae029

101441003561 has 2 divisors, whose sum is σ = 101441003562. Its totient is φ = 101441003560.

The previous prime is 101441003551. The next prime is 101441003563. The reversal of 101441003561 is 165300144101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88973941225 + 12467062336 = 298285^2 + 111656^2 .

It is a cyclic number.

It is not a de Polignac number, because 101441003561 - 214 = 101440987177 is a prime.

Together with 101441003563, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101441003561.

It is not a weakly prime, because it can be changed into another prime (101441003563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50720501780 + 50720501781.

It is an arithmetic number, because the mean of its divisors is an integer number (50720501781).

Almost surely, 2101441003561 is an apocalyptic number.

It is an amenable number.

101441003561 is a deficient number, since it is larger than the sum of its proper divisors (1).

101441003561 is an equidigital number, since it uses as much as digits as its factorization.

101441003561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 101441003561 its reverse (165300144101), we get a palindrome (266741147662).

The spelling of 101441003561 in words is "one hundred one billion, four hundred forty-one million, three thousand, five hundred sixty-one".