Base | Representation |
---|---|
bin | 10010111001010001… |
… | …11000011000101101 |
3 | 222011222000110212011 |
4 | 21130220320120231 |
5 | 131233400431211 |
6 | 4354332241221 |
7 | 506244616306 |
oct | 113450703055 |
9 | 28158013764 |
10 | 10144155181 |
11 | 4336124a26 |
12 | 1b71310211 |
13 | c58820bb4 |
14 | 6c33697ad |
15 | 3e5885921 |
hex | 25ca3862d |
10144155181 has 2 divisors, whose sum is σ = 10144155182. Its totient is φ = 10144155180.
The previous prime is 10144155173. The next prime is 10144155193. The reversal of 10144155181 is 18155144101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9010755625 + 1133399556 = 94925^2 + 33666^2 .
It is a cyclic number.
It is not a de Polignac number, because 10144155181 - 23 = 10144155173 is a prime.
It is a super-2 number, since 2×101441551812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10144155881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072077590 + 5072077591.
It is an arithmetic number, because the mean of its divisors is an integer number (5072077591).
Almost surely, 210144155181 is an apocalyptic number.
It is an amenable number.
10144155181 is a deficient number, since it is larger than the sum of its proper divisors (1).
10144155181 is an equidigital number, since it uses as much as digits as its factorization.
10144155181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3200, while the sum is 31.
Adding to 10144155181 its reverse (18155144101), we get a palindrome (28299299282).
The spelling of 10144155181 in words is "ten billion, one hundred forty-four million, one hundred fifty-five thousand, one hundred eighty-one".
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