Base | Representation |
---|---|
bin | 10111000100001011010100… |
… | …010111001000100100010111 |
3 | 111022011202210101200211002111 |
4 | 113010023110113020210113 |
5 | 101244011410202244002 |
6 | 555425505123451451 |
7 | 30236643546434101 |
oct | 2704132427104427 |
9 | 438152711624074 |
10 | 101442100431127 |
11 | 2a3603981154a5 |
12 | b4641aa226b87 |
13 | 447ac45011511 |
14 | 1b09b76948571 |
15 | badb1da163d7 |
hex | 5c42d45c8917 |
101442100431127 has 2 divisors, whose sum is σ = 101442100431128. Its totient is φ = 101442100431126.
The previous prime is 101442100431071. The next prime is 101442100431163. The reversal of 101442100431127 is 721134001244101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101442100431127 - 223 = 101442092042519 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101442100431167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50721050215563 + 50721050215564.
It is an arithmetic number, because the mean of its divisors is an integer number (50721050215564).
Almost surely, 2101442100431127 is an apocalyptic number.
101442100431127 is a deficient number, since it is larger than the sum of its proper divisors (1).
101442100431127 is an equidigital number, since it uses as much as digits as its factorization.
101442100431127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 31.
Adding to 101442100431127 its reverse (721134001244101), we get a palindrome (822576101675228).
The spelling of 101442100431127 in words is "one hundred one trillion, four hundred forty-two billion, one hundred million, four hundred thirty-one thousand, one hundred twenty-seven".
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