10144213333 has 4 divisors (see below), whose sum is σ = 10221650208. Its totient is φ = 10066776460.

The previous prime is 10144213307. The next prime is 10144213337. The reversal of 10144213333 is 33331244101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10144213333 - 2⁵ = 10144213301 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10144213298 and 10144213307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10144213337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38718241 + ... + 38718502.

It is an arithmetic number, because the mean of its divisors is an integer number (2555412552).

Almost surely, 2^10144213333 is an apocalyptic number.

It is an amenable number.

10144213333 is a deficient number, since it is larger than the sum of its proper divisors (77436875).

10144213333 is an equidigital number, since it uses as much as digits as its factorization.

10144213333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77436874.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 10144213333 its reverse (33331244101), we get a palindrome (43475457434).

The spelling of 10144213333 in words is "ten billion, one hundred forty-four million, two hundred thirteen thousand, three hundred thirty-three".