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101453256433 is a prime number
BaseRepresentation
bin101111001111100010…
…1011101011011110001
3100200212110012102022001
41132133011131123301
53130234013201213
6114335035214001
710221051310504
oct1363705353361
9320773172261
10101453256433
113a03179a181
12177b45a7301
13974a9168a9
144ca607713b
15298baee1dd
hex179f15d6f1

101453256433 has 2 divisors, whose sum is σ = 101453256434. Its totient is φ = 101453256432.

The previous prime is 101453256419. The next prime is 101453256467. The reversal of 101453256433 is 334652354101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82976835249 + 18476421184 = 288057^2 + 135928^2 .

It is a cyclic number.

It is not a de Polignac number, because 101453256433 - 233 = 92863321841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101453256392 and 101453256401.

It is not a weakly prime, because it can be changed into another prime (101453256133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50726628216 + 50726628217.

It is an arithmetic number, because the mean of its divisors is an integer number (50726628217).

Almost surely, 2101453256433 is an apocalyptic number.

It is an amenable number.

101453256433 is a deficient number, since it is larger than the sum of its proper divisors (1).

101453256433 is an equidigital number, since it uses as much as digits as its factorization.

101453256433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 37.

The spelling of 101453256433 in words is "one hundred one billion, four hundred fifty-three million, two hundred fifty-six thousand, four hundred thirty-three".