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1014682515131 is a prime number
BaseRepresentation
bin11101100001111111100…
…10100111011010111011
310121000001222011110210202
432300333302213122323
5113111032210441011
62054045543432415
7133210531033415
oct16607762473273
93530058143722
101014682515131
1136136291091a
1214479b15570b
13748b810440c
143717a4259b5
151b5da76623b
hexec3fca76bb

1014682515131 has 2 divisors, whose sum is σ = 1014682515132. Its totient is φ = 1014682515130.

The previous prime is 1014682515109. The next prime is 1014682515169. The reversal of 1014682515131 is 1315152864101.

It is an a-pointer prime, because the next prime (1014682515169) can be obtained adding 1014682515131 to its sum of digits (38).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1014682515131 - 210 = 1014682514107 is a prime.

It is a super-2 number, since 2×10146825151312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1014682515631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507341257565 + 507341257566.

It is an arithmetic number, because the mean of its divisors is an integer number (507341257566).

Almost surely, 21014682515131 is an apocalyptic number.

1014682515131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1014682515131 is an equidigital number, since it uses as much as digits as its factorization.

1014682515131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 38.

The spelling of 1014682515131 in words is "one trillion, fourteen billion, six hundred eighty-two million, five hundred fifteen thousand, one hundred thirty-one".