Base | Representation |
---|---|
bin | 11101100001111111100… |
… | …10100111011010111011 |
3 | 10121000001222011110210202 |
4 | 32300333302213122323 |
5 | 113111032210441011 |
6 | 2054045543432415 |
7 | 133210531033415 |
oct | 16607762473273 |
9 | 3530058143722 |
10 | 1014682515131 |
11 | 36136291091a |
12 | 14479b15570b |
13 | 748b810440c |
14 | 3717a4259b5 |
15 | 1b5da76623b |
hex | ec3fca76bb |
1014682515131 has 2 divisors, whose sum is σ = 1014682515132. Its totient is φ = 1014682515130.
The previous prime is 1014682515109. The next prime is 1014682515169. The reversal of 1014682515131 is 1315152864101.
It is an a-pointer prime, because the next prime (1014682515169) can be obtained adding 1014682515131 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1014682515131 - 210 = 1014682514107 is a prime.
It is a super-2 number, since 2×10146825151312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1014682515631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507341257565 + 507341257566.
It is an arithmetic number, because the mean of its divisors is an integer number (507341257566).
Almost surely, 21014682515131 is an apocalyptic number.
1014682515131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1014682515131 is an equidigital number, since it uses as much as digits as its factorization.
1014682515131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 38.
The spelling of 1014682515131 in words is "one trillion, fourteen billion, six hundred eighty-two million, five hundred fifteen thousand, one hundred thirty-one".
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