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101484044749 is a prime number
BaseRepresentation
bin101111010000011101…
…0111010000111001101
3100200221121010121221001
41132200322322013031
53130314403412444
6114342055140301
710221604101403
oct1364072720715
9320847117831
10101484044749
113a04810896a
1217802974691
139754106629
144caa1ad473
15298e6818d4
hex17a0eba1cd

101484044749 has 2 divisors, whose sum is σ = 101484044750. Its totient is φ = 101484044748.

The previous prime is 101484044729. The next prime is 101484044759. The reversal of 101484044749 is 947440484101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95722172100 + 5761872649 = 309390^2 + 75907^2 .

It is an emirp because it is prime and its reverse (947440484101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101484044749 - 211 = 101484042701 is a prime.

It is a super-2 number, since 2×1014840447492 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101484044699 and 101484044708.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101484044729) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50742022374 + 50742022375.

It is an arithmetic number, because the mean of its divisors is an integer number (50742022375).

Almost surely, 2101484044749 is an apocalyptic number.

It is an amenable number.

101484044749 is a deficient number, since it is larger than the sum of its proper divisors (1).

101484044749 is an equidigital number, since it uses as much as digits as its factorization.

101484044749 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 516096, while the sum is 46.

The spelling of 101484044749 in words is "one hundred one billion, four hundred eighty-four million, forty-four thousand, seven hundred forty-nine".