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10153714105147 is a prime number
BaseRepresentation
bin1001001111000001100010…
…0001011011101100111011
31022221200111210102212010211
42103300120201123230323
52312324301302331042
633332315111451551
72065403333600404
oct223603041335473
938850453385124
1010153714105147
1132651909a6358
12117ba36386bb7
13588650029822
14271629c929ab
151291c4b23017
hex93c1885bb3b

10153714105147 has 2 divisors, whose sum is σ = 10153714105148. Its totient is φ = 10153714105146.

The previous prime is 10153714105133. The next prime is 10153714105187. The reversal of 10153714105147 is 74150141735101.

10153714105147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (10153714105187) can be obtained adding 10153714105147 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10153714105147 - 215 = 10153714072379 is a prime.

It is a super-2 number, since 2×101537141051472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10153714105187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5076857052573 + 5076857052574.

It is an arithmetic number, because the mean of its divisors is an integer number (5076857052574).

Almost surely, 210153714105147 is an apocalyptic number.

10153714105147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10153714105147 is an equidigital number, since it uses as much as digits as its factorization.

10153714105147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58800, while the sum is 40.

The spelling of 10153714105147 in words is "ten trillion, one hundred fifty-three billion, seven hundred fourteen million, one hundred five thousand, one hundred forty-seven".