101538648103391 has 4 divisors (see below), whose sum is σ = 101647013790672. Its totient is φ = 101430282416112.

The previous prime is 101538648103357. The next prime is 101538648103429. The reversal of 101538648103391 is 193301846835101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101538648103391 is a prime.

It is a super-3 number, since 3×101538648103391³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101538648103691) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54182842235 + ... + 54182844108.

It is an arithmetic number, because the mean of its divisors is an integer number (25411753447668).

Almost surely, 2^{101538648103391} is an apocalyptic number.

101538648103391 is a deficient number, since it is larger than the sum of its proper divisors (108365687281).

101538648103391 is an equidigital number, since it uses as much as digits as its factorization.

101538648103391 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 108365687280.

The product of its (nonzero) digits is 1866240, while the sum is 53.

The spelling of 101538648103391 in words is "one hundred one trillion, five hundred thirty-eight billion, six hundred forty-eight million, one hundred three thousand, three hundred ninety-one".