Base | Representation |
---|---|
bin | 101111010010100010… |
… | …0000011100001010001 |
3 | 100201010102220221011222 |
4 | 1132211010003201101 |
5 | 3130440202121231 |
6 | 114353021014425 |
7 | 10223406641666 |
oct | 1364504034121 |
9 | 321112827158 |
10 | 101553551441 |
11 | 3a083372311 |
12 | 178220b4415 |
13 | 9765631754 |
14 | 4cb5503a6d |
15 | 299581127b |
hex | 17a5103851 |
101553551441 has 2 divisors, whose sum is σ = 101553551442. Its totient is φ = 101553551440.
The previous prime is 101553551431. The next prime is 101553551443. The reversal of 101553551441 is 144155355101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100017225025 + 1536326416 = 316255^2 + 39196^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101553551441 is a prime.
Together with 101553551443, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (101553551443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50776775720 + 50776775721.
It is an arithmetic number, because the mean of its divisors is an integer number (50776775721).
Almost surely, 2101553551441 is an apocalyptic number.
It is an amenable number.
101553551441 is a deficient number, since it is larger than the sum of its proper divisors (1).
101553551441 is an equidigital number, since it uses as much as digits as its factorization.
101553551441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30000, while the sum is 35.
The spelling of 101553551441 in words is "one hundred one billion, five hundred fifty-three million, five hundred fifty-one thousand, four hundred forty-one".
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