Base | Representation |
---|---|
bin | 101111010101001001… |
… | …1010111111001010101 |
3 | 100201100120022210122111 |
4 | 1132222103113321111 |
5 | 3131130203000031 |
6 | 114405441031021 |
7 | 10225525045114 |
oct | 1365223277125 |
9 | 321316283574 |
10 | 101641453141 |
11 | 3a118a50148 |
12 | 17847625471 |
13 | 977a8ca5a7 |
14 | 4cc3065c7b |
15 | 299d3c61b1 |
hex | 17aa4d7e55 |
101641453141 has 2 divisors, whose sum is σ = 101641453142. Its totient is φ = 101641453140.
The previous prime is 101641453127. The next prime is 101641453163. The reversal of 101641453141 is 141354146101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99887602500 + 1753850641 = 316050^2 + 41879^2 .
It is a cyclic number.
It is not a de Polignac number, because 101641453141 - 225 = 101607898709 is a prime.
It is a super-2 number, since 2×1016414531412 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101641453541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50820726570 + 50820726571.
It is an arithmetic number, because the mean of its divisors is an integer number (50820726571).
Almost surely, 2101641453141 is an apocalyptic number.
It is an amenable number.
101641453141 is a deficient number, since it is larger than the sum of its proper divisors (1).
101641453141 is an equidigital number, since it uses as much as digits as its factorization.
101641453141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 101641453141 its reverse (141354146101), we get a palindrome (242995599242).
The spelling of 101641453141 in words is "one hundred one billion, six hundred forty-one million, four hundred fifty-three thousand, one hundred forty-one".
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