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10164455151 = 33388151717
BaseRepresentation
bin10010111011101100…
…10100011011101111
3222020101012211011220
421131312110123233
5131304100031101
64400335314423
7506612305014
oct113566243357
928211184156
1010164455151
11434662a664
121b7807ba13
13c5caaaa06
146c5d3170b
153e7545636
hex25dd946ef

10164455151 has 4 divisors (see below), whose sum is σ = 13552606872. Its totient is φ = 6776303432.

The previous prime is 10164455117. The next prime is 10164455153. The reversal of 10164455151 is 15155446101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15155446101 = 35051815367.

It is a cyclic number.

It is not a de Polignac number, because 10164455151 - 219 = 10163930863 is a prime.

It is a super-2 number, since 2×101644551512 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10164455153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1694075856 + ... + 1694075861.

It is an arithmetic number, because the mean of its divisors is an integer number (3388151718).

Almost surely, 210164455151 is an apocalyptic number.

10164455151 is a deficient number, since it is larger than the sum of its proper divisors (3388151721).

10164455151 is an equidigital number, since it uses as much as digits as its factorization.

10164455151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3388151720.

The product of its (nonzero) digits is 12000, while the sum is 33.

The spelling of 10164455151 in words is "ten billion, one hundred sixty-four million, four hundred fifty-five thousand, one hundred fifty-one".

Divisors: 1 3 3388151717 10164455151