10164703111 has 2 divisors, whose sum is σ = 10164703112. Its totient is φ = 10164703110.

The previous prime is 10164703093. The next prime is 10164703117. The reversal of 10164703111 is 11130746101.

It is a strong prime.

It is an emirp because it is prime and its reverse (11130746101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10164703111 - 2⁵ = 10164703079 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10164703117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5082351555 + 5082351556.

It is an arithmetic number, because the mean of its divisors is an integer number (5082351556).

Almost surely, 2^10164703111 is an apocalyptic number.

10164703111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10164703111 is an equidigital number, since it uses as much as digits as its factorization.

10164703111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 25.

Subtracting 10164703111 from its reverse (11130746101), we obtain a triangular number (966042990 = T₄₃₉₅₅).

The spelling of 10164703111 in words is "ten billion, one hundred sixty-four million, seven hundred three thousand, one hundred eleven".