Base | Representation |
---|---|
bin | 10010111100100000… |
… | …10011110000100101 |
3 | 222020212000221211120 |
4 | 21132100103300211 |
5 | 131312321040013 |
6 | 4401141324153 |
7 | 510024231645 |
oct | 113620236045 |
9 | 28225027746 |
10 | 10171268133 |
11 | 434a463324 |
12 | 1b7a406659 |
13 | c61324a70 |
14 | 6c6bc6525 |
15 | 3e7e3e123 |
hex | 25e413c25 |
10171268133 has 32 divisors (see below), whose sum is σ = 14715872640. Its totient is φ = 6211829760.
The previous prime is 10171268111. The next prime is 10171268137. The reversal of 10171268133 is 33186217101.
It is not a de Polignac number, because 10171268133 - 28 = 10171267877 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10171268094 and 10171268103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10171268137) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4473685 + ... + 4475957.
It is an arithmetic number, because the mean of its divisors is an integer number (459871020).
Almost surely, 210171268133 is an apocalyptic number.
10171268133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
10171268133 is a deficient number, since it is larger than the sum of its proper divisors (4544604507).
10171268133 is a wasteful number, since it uses less digits than its factorization.
10171268133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3109.
The product of its (nonzero) digits is 6048, while the sum is 33.
The spelling of 10171268133 in words is "ten billion, one hundred seventy-one million, two hundred sixty-eight thousand, one hundred thirty-three".
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