Base | Representation |
---|---|
bin | 10111001100011101001111… |
… | …011111111010001101100001 |
3 | 111101012011111002120000222221 |
4 | 113030131033133322031201 |
5 | 101332322214103343012 |
6 | 1000543130414231041 |
7 | 30326026130166064 |
oct | 2714351737721541 |
9 | 441164432500887 |
10 | 102011102012257 |
11 | 2a55a7357310a9 |
12 | b5365277b5481 |
13 | 44bc7b47a1329 |
14 | 1b29513d288db |
15 | bbd82228c507 |
hex | 5cc74f7fa361 |
102011102012257 has 2 divisors, whose sum is σ = 102011102012258. Its totient is φ = 102011102012256.
The previous prime is 102011102012207. The next prime is 102011102012279. The reversal of 102011102012257 is 752210201110201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101388164350561 + 622937661696 = 10069169^2 + 789264^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102011102012257 is a prime.
It is not a weakly prime, because it can be changed into another prime (102011102012207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51005551006128 + 51005551006129.
It is an arithmetic number, because the mean of its divisors is an integer number (51005551006129).
Almost surely, 2102011102012257 is an apocalyptic number.
It is an amenable number.
102011102012257 is a deficient number, since it is larger than the sum of its proper divisors (1).
102011102012257 is an equidigital number, since it uses as much as digits as its factorization.
102011102012257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 25.
Adding to 102011102012257 its reverse (752210201110201), we get a palindrome (854221303122458).
The spelling of 102011102012257 in words is "one hundred two trillion, eleven billion, one hundred two million, twelve thousand, two hundred fifty-seven".
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