Base | Representation |
---|---|
bin | 101111100000001100… |
… | …1101111001010000001 |
3 | 100202022101222201012121 |
4 | 1133000121233022001 |
5 | 3132410112020113 |
6 | 114510323524241 |
7 | 10240646364133 |
oct | 1370031571201 |
9 | 322271881177 |
10 | 102012220033 |
11 | 3a299269869 |
12 | 1792b829681 |
13 | 9809674c99 |
14 | 4d1a3bb053 |
15 | 29c0c12e8d |
hex | 17c066f281 |
102012220033 has 4 divisors (see below), whose sum is σ = 102013758000. Its totient is φ = 102010682068.
The previous prime is 102012219977. The next prime is 102012220099. The reversal of 102012220033 is 330022210201.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 330022210201 = 151 ⋅2185577551.
It is a cyclic number.
It is not a de Polignac number, because 102012220033 - 221 = 102010122881 is a prime.
It is a super-2 number, since 2×1020122200332 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 102012219989 and 102012220016.
It is not an unprimeable number, because it can be changed into a prime (102012220333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 664783 + ... + 803716.
It is an arithmetic number, because the mean of its divisors is an integer number (25503439500).
Almost surely, 2102012220033 is an apocalyptic number.
It is an amenable number.
102012220033 is a deficient number, since it is larger than the sum of its proper divisors (1537967).
102012220033 is an equidigital number, since it uses as much as digits as its factorization.
102012220033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1537966.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 102012220033 its reverse (330022210201), we get a palindrome (432034430234).
The spelling of 102012220033 in words is "one hundred two billion, twelve million, two hundred twenty thousand, thirty-three".
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