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1020131000131 = 2935176931039
BaseRepresentation
bin11101101100001001000…
…10111011111101000011
310121112010200110012010111
432312010202323331003
5113203212014001011
62100350335412151
7133462540300345
oct16660442737503
93545120405114
101020131000131
113636a939a291
1214585b984057
1375275b4c239
1437535cad295
151b808c5c121
hexed848bbf43

1020131000131 has 4 divisors (see below), whose sum is σ = 1055307931200. Its totient is φ = 984954069064.

The previous prime is 1020131000123. The next prime is 1020131000177. The reversal of 1020131000131 is 1310001310201.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1020131000131 - 23 = 1020131000123 is a prime.

It is a super-2 number, since 2×10201310001312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1020131000731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17588465491 + ... + 17588465548.

It is an arithmetic number, because the mean of its divisors is an integer number (263826982800).

Almost surely, 21020131000131 is an apocalyptic number.

1020131000131 is a deficient number, since it is larger than the sum of its proper divisors (35176931069).

1020131000131 is an equidigital number, since it uses as much as digits as its factorization.

1020131000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35176931068.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1020131000131 its reverse (1310001310201), we get a palindrome (2330132310332).

The spelling of 1020131000131 in words is "one trillion, twenty billion, one hundred thirty-one million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 29 35176931039 1020131000131