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10203013000311 = 33401004333437
BaseRepresentation
bin1001010001111001001011…
…1101110010110001110111
31100010101202112000012201220
42110132102331302301313
52314131232312002221
633411111030121423
72102100113360625
oct224362275626167
940111675005656
1010203013000311
113284089934a1a
1211894b44b0273
135901a8761301
14273b8543c515
1512a60cb780c6
hex94792f72c77

10203013000311 has 4 divisors (see below), whose sum is σ = 13604017333752. Its totient is φ = 6802008666872.

The previous prime is 10203013000273. The next prime is 10203013000319. The reversal of 10203013000311 is 11300031030201.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10203013000311 - 29 = 10203012999799 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10203013000319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1700502166716 + ... + 1700502166721.

It is an arithmetic number, because the mean of its divisors is an integer number (3401004333438).

Almost surely, 210203013000311 is an apocalyptic number.

10203013000311 is a deficient number, since it is larger than the sum of its proper divisors (3401004333441).

10203013000311 is an equidigital number, since it uses as much as digits as its factorization.

10203013000311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3401004333440.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10203013000311 its reverse (11300031030201), we get a palindrome (21503044030512).

The spelling of 10203013000311 in words is "ten trillion, two hundred three billion, thirteen million, three hundred eleven", and thus it is an aban number.

Divisors: 1 3 3401004333437 10203013000311