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102043320130 = 2510204332013
BaseRepresentation
bin101111100001001000…
…0010111111101000010
3100202101120111202112001
41133002100113331002
53132441042221010
6114513354254214
710241504624023
oct1370220277502
9322346452461
10102043320130
113a304880824
121793a12736a
139812c438cb
144d20594c4a
1529c3807c3a
hex17c2417f42

102043320130 has 8 divisors (see below), whose sum is σ = 183677976252. Its totient is φ = 40817328048.

The previous prime is 102043320079. The next prime is 102043320193. The reversal of 102043320130 is 31023340201.

It can be written as a sum of positive squares in 2 ways, for example, as 101511694881 + 531625249 = 318609^2 + 23057^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 102043320098 and 102043320107.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5102165997 + ... + 5102166016.

Almost surely, 2102043320130 is an apocalyptic number.

102043320130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

102043320130 is a deficient number, since it is larger than the sum of its proper divisors (81634656122).

102043320130 is a wasteful number, since it uses less digits than its factorization.

102043320130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10204332020.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 102043320130 its reverse (31023340201), we get a palindrome (133066660331).

The spelling of 102043320130 in words is "one hundred two billion, forty-three million, three hundred twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 10204332013 20408664026 51021660065 102043320130