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10204335421055 = 559100549344021
BaseRepresentation
bin1001010001111110000111…
…0010011011011001111111
31100010112011200101010221222
42110133201302123121333
52314141434331433210
633411450150143555
72102144641641656
oct224374162333177
940115150333858
1010204335421055
1132846a8356226
121189803351bbb
135903597194a9
14273c6cd1819d
1512a688ce6655
hex947e1c9b67f

10204335421055 has 16 divisors (see below), whose sum is σ = 12452908356000. Its totient is φ = 8025001326720.

The previous prime is 10204335421037. The next prime is 10204335421079. The reversal of 10204335421055 is 55012453340201.

It is not a de Polignac number, because 10204335421055 - 218 = 10204335158911 is a prime.

It is a super-2 number, since 2×102043354210552 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29489945 + ... + 29833965.

It is an arithmetic number, because the mean of its divisors is an integer number (778306772250).

Almost surely, 210204335421055 is an apocalyptic number.

10204335421055 is a deficient number, since it is larger than the sum of its proper divisors (2248572934945).

10204335421055 is a wasteful number, since it uses less digits than its factorization.

10204335421055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 444634.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 10204335421055 its reverse (55012453340201), we get a palindrome (65216788761256).

The spelling of 10204335421055 in words is "ten trillion, two hundred four billion, three hundred thirty-five million, four hundred twenty-one thousand, fifty-five".

Divisors: 1 5 59 295 100549 344021 502745 1720105 5932391 20297239 29661955 101486195 34590967529 172954837645 2040867084211 10204335421055