Base | Representation |
---|---|
bin | 1001010001111110011100… |
… | …1100000111111111000111 |
3 | 1100010112101222220020100201 |
4 | 2110133213030013333013 |
5 | 2314142131031341320 |
6 | 33411503144351331 |
7 | 2102150122135606 |
oct | 224374714077707 |
9 | 40115358806321 |
10 | 10204426043335 |
11 | 3284744522077 |
12 | 1189829775547 |
13 | 590372428744 |
14 | 273c7ad87a3d |
15 | 12a691c4770a |
hex | 947e7307fc7 |
10204426043335 has 16 divisors (see below), whose sum is σ = 12679616420640. Its totient is φ = 7874539747200.
The previous prime is 10204426043323. The next prime is 10204426043359. The reversal of 10204426043335 is 53334062440201.
It is not a de Polignac number, because 10204426043335 - 225 = 10204392488903 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10204426043294 and 10204426043303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33327792 + ... + 33632581.
It is an arithmetic number, because the mean of its divisors is an integer number (792476026290).
Almost surely, 210204426043335 is an apocalyptic number.
10204426043335 is a deficient number, since it is larger than the sum of its proper divisors (2475190377305).
10204426043335 is a wasteful number, since it uses less digits than its factorization.
10204426043335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66961458.
The product of its (nonzero) digits is 207360, while the sum is 37.
Adding to 10204426043335 its reverse (53334062440201), we get a palindrome (63538488483536).
The spelling of 10204426043335 in words is "ten trillion, two hundred four billion, four hundred twenty-six million, forty-three thousand, three hundred thirty-five".
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