Base | Representation |
---|---|
bin | 11101101101110000110… |
… | …10001110010110000111 |
3 | 10121121101022202102211111 |
4 | 32312320122032112013 |
5 | 113212002242201044 |
6 | 2101012541345451 |
7 | 133523234265244 |
oct | 16667032162607 |
9 | 3547338672744 |
10 | 1021001131399 |
11 | 364005580837 |
12 | 145a63268287 |
13 | 753841b8602 |
14 | 375b96925cb |
15 | 1b85a338b34 |
hex | edb868e587 |
1021001131399 has 2 divisors, whose sum is σ = 1021001131400. Its totient is φ = 1021001131398.
The previous prime is 1021001131391. The next prime is 1021001131417. The reversal of 1021001131399 is 9931311001201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021001131399 - 23 = 1021001131391 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1021001131399.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021001131391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510500565699 + 510500565700.
It is an arithmetic number, because the mean of its divisors is an integer number (510500565700).
Almost surely, 21021001131399 is an apocalyptic number.
1021001131399 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021001131399 is an equidigital number, since it uses as much as digits as its factorization.
1021001131399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 31.
The spelling of 1021001131399 in words is "one trillion, twenty-one billion, one million, one hundred thirty-one thousand, three hundred ninety-nine".
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