Base | Representation |
---|---|
bin | 10111001101110000111110… |
… | …011111111100001111110111 |
3 | 111101111202120000101222221201 |
4 | 113031300332133330033313 |
5 | 101340310332321334033 |
6 | 1001052320150353331 |
7 | 30335361144046006 |
oct | 2715607637741767 |
9 | 441452500358851 |
10 | 102101011121143 |
11 | 2a594883012371 |
12 | b54ba3a05b847 |
13 | 44c811281bb88 |
14 | 1b2da02b26c3d |
15 | bc0d3566347d |
hex | 5cdc3e7fc3f7 |
102101011121143 has 2 divisors, whose sum is σ = 102101011121144. Its totient is φ = 102101011121142.
The previous prime is 102101011121107. The next prime is 102101011121191. The reversal of 102101011121143 is 341121110101201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 102101011121143 - 225 = 102100977566711 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 102101011121143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102101011131143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51050505560571 + 51050505560572.
It is an arithmetic number, because the mean of its divisors is an integer number (51050505560572).
Almost surely, 2102101011121143 is an apocalyptic number.
102101011121143 is a deficient number, since it is larger than the sum of its proper divisors (1).
102101011121143 is an equidigital number, since it uses as much as digits as its factorization.
102101011121143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 102101011121143 its reverse (341121110101201), we get a palindrome (443222121222344).
The spelling of 102101011121143 in words is "one hundred two trillion, one hundred one billion, eleven million, one hundred twenty-one thousand, one hundred forty-three".
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