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10210213131 = 34321840673
BaseRepresentation
bin10011000001001001…
…10111110100001011
3222100120022120022220
421200210313310023
5131402303310011
64405052145123
7511006244136
oct114044676413
928316276286
1010210213131
11436a443278
121b8b4681a3
13c6940c341
146cc04321d
153eb583506
hex260937d0b

10210213131 has 12 divisors (see below), whose sum is σ = 13937583528. Its totient is φ = 6648507264.

The previous prime is 10210213099. The next prime is 10210213201. The reversal of 10210213131 is 13131201201.

It is a happy number.

It is not a de Polignac number, because 10210213131 - 25 = 10210213099 is a prime.

It is a super-2 number, since 2×102102131312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10210213131.

It is not an unprimeable number, because it can be changed into a prime (10210211131) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 914790 + ... + 925883.

It is an arithmetic number, because the mean of its divisors is an integer number (1161465294).

Almost surely, 210210213131 is an apocalyptic number.

10210213131 is a deficient number, since it is larger than the sum of its proper divisors (3727370397).

10210213131 is an equidigital number, since it uses as much as digits as its factorization.

10210213131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1840762 (or 1840719 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 10210213131 its reverse (13131201201), we get a palindrome (23341414332).

The spelling of 10210213131 in words is "ten billion, two hundred ten million, two hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 3 43 129 1849 5547 1840673 5522019 79148939 237446817 3403404377 10210213131