Base | Representation |
---|---|
bin | 11101101101110100011… |
… | …01010011101110100011 |
3 | 10121121110102112011101012 |
4 | 32312322031103232203 |
5 | 113212033003100003 |
6 | 2101015540131135 |
7 | 133524051565331 |
oct | 16667215235643 |
9 | 3547412464335 |
10 | 1021031300003 |
11 | 364020606970 |
12 | 145a71396aab |
13 | 7538a51c260 |
14 | 375bd6a6b51 |
15 | 1b85cce78d8 |
hex | edba353ba3 |
1021031300003 has 16 divisors (see below), whose sum is σ = 1199758511616. Its totient is φ = 856648599840.
The previous prime is 1021031299993. The next prime is 1021031300059. The reversal of 1021031300003 is 3000031301201.
It is not a de Polignac number, because 1021031300003 - 234 = 1003851430819 is a prime.
It is a super-3 number, since 3×10210313000033 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1021031330003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 96950 + ... + 1432292.
It is an arithmetic number, because the mean of its divisors is an integer number (74984906976).
Almost surely, 21021031300003 is an apocalyptic number.
1021031300003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1021031300003 is a deficient number, since it is larger than the sum of its proper divisors (178727211613).
1021031300003 is a wasteful number, since it uses less digits than its factorization.
1021031300003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1340714.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 1021031300003 its reverse (3000031301201), we get a palindrome (4021062601204).
The spelling of 1021031300003 in words is "one trillion, twenty-one billion, thirty-one million, three hundred thousand, three".
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