Base | Representation |
---|---|
bin | 11101101101110100011… |
… | …01011000100110000101 |
3 | 10121121110102120011201122 |
4 | 32312322031120212011 |
5 | 113212033004214231 |
6 | 2101015540403325 |
7 | 133524052010423 |
oct | 16667215304605 |
9 | 3547412504648 |
10 | 1021031319941 |
11 | 36402061a946 |
12 | 145a713a6545 |
13 | 7538a528359 |
14 | 375bd6b0113 |
15 | 1b85cced77b |
hex | edba358985 |
1021031319941 has 2 divisors, whose sum is σ = 1021031319942. Its totient is φ = 1021031319940.
The previous prime is 1021031319907. The next prime is 1021031320039. The reversal of 1021031319941 is 1499131301201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 647575887841 + 373455432100 = 804721^2 + 611110^2 .
It is an emirp because it is prime and its reverse (1499131301201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1021031319941 - 214 = 1021031303557 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021031312941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510515659970 + 510515659971.
It is an arithmetic number, because the mean of its divisors is an integer number (510515659971).
Almost surely, 21021031319941 is an apocalyptic number.
It is an amenable number.
1021031319941 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021031319941 is an equidigital number, since it uses as much as digits as its factorization.
1021031319941 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 35.
The spelling of 1021031319941 in words is "one trillion, twenty-one billion, thirty-one million, three hundred nineteen thousand, nine hundred forty-one".
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