Base | Representation |
---|---|
bin | 101111100010111010… |
… | …1010000011000110001 |
3 | 100202112202102002000122 |
4 | 1133011311100120301 |
5 | 3133101422220423 |
6 | 114523340300025 |
7 | 10243133621054 |
oct | 1370565203061 |
9 | 322482362018 |
10 | 102103320113 |
11 | 3a335731693 |
12 | 17956241615 |
13 | 98224c0862 |
14 | 4d28532a9b |
15 | 29c8c0a8c8 |
hex | 17c5d50631 |
102103320113 has 2 divisors, whose sum is σ = 102103320114. Its totient is φ = 102103320112.
The previous prime is 102103320103. The next prime is 102103320173. The reversal of 102103320113 is 311023301201.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 78406720144 + 23696599969 = 280012^2 + 153937^2 .
It is an emirp because it is prime and its reverse (311023301201) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102103320113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102103320091 and 102103320100.
It is not a weakly prime, because it can be changed into another prime (102103320103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51051660056 + 51051660057.
It is an arithmetic number, because the mean of its divisors is an integer number (51051660057).
Almost surely, 2102103320113 is an apocalyptic number.
It is an amenable number.
102103320113 is a deficient number, since it is larger than the sum of its proper divisors (1).
102103320113 is an equidigital number, since it uses as much as digits as its factorization.
102103320113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 102103320113 its reverse (311023301201), we get a palindrome (413126621314).
The spelling of 102103320113 in words is "one hundred two billion, one hundred three million, three hundred twenty thousand, one hundred thirteen".
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